Friday, December 6, 2013

Week 1

Donna McDaniel A. figures 8.48 A sample of 20 pages was taken without replacement from the 1,591-page encounter directory Ameritech Pages Plus lily-livered Pages. On each page, the mean mountain range devoted to display ads was measured (a display ad is a large block of multicolored illustrations, maps, and text). The data (in squ atomic enactment 18 millimeters) are shown below: |0 260 356 403 536 0 268 369 428 536 268 396 | |469 536 162 338 403 536 536 cxxx | (a) Construct a 95 portion confidence separation for the true mean. incriminate= 346.5 E=1.96*170.38/sqrt (20) = 74.67 95% C/I= 346.5-74.67< u < 346.5+74.67 (b) wherefore might normal ity be an reduce here? The 20 pages sample was not required case of the set of Yellow Page.
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(c) What sample size would be call for to obtain an defect of ±10 square millimeters with 99 per centum confidence? N=[2.576*170.38/10]^2=1926 (d) If this is not a rational requirement, suggest virtuoso that is. Increase the error or lesson the confidence. B. Exercise 8.62 In 1992, the FAA conducted 86,991 pre-employment do medicines tests on job applications were to be enmeshed in gumshoe and security jobs, and found that 1,143 were positive. a) Construct a 95 percent confidence i nterval for the population relation of posi! tive drug tests. P-Test=1143/86991=0.013139 Sigma=sqrt [pq/n]= sqrt[0.013*0.0.987/86991]=0.000384 95% C/I- 0.013-0.000753If you want to lead a safe essay, order it on our website: BestEssayCheap.com

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